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Re: Physics: Electric Fields
F = q1 q2 / r^2 * epsilon 0 if I remember right.
If q1 is -ve, then unless q2 is also -ve, F will be negitive. So if you replace one charge with an equal but opposite charge, you will get an equil but opposite force.
So yes, ANS c = - ANS b
3) again, if a -ve charge will go to the left, a +ve charge will go to the right so the E field also goes to the right.
4) Both plates will be at the same VOLTAGE. Thus, for the potential energy at every part of the plate to be even, the charge density must also be even. Thus, by symetry, the E field is constant between the plates (ignoring edge effects).
Will think about the others.
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