Science Forums 2

[CraigD]

Originally Posted by Don Blazys

(T/T)a^x+(T/T)b^y=(T/T)c^z=

T(c/T)^((zln(c)/(ln(T))-1)/(ln(c)/(ln(T))-1)).

Factoring does not involve the cancelled variable T, and results in:

((T/T)a^(x/2))^2+((T/T)b^(y/2))^2=((T/T)c^(z/2))^2=

(T(c/T)^(((z/2)ln(c)/(ln(T))-1)/(ln(c)/(ln(T))-1)))^2,

This step is algebraically incorrect. It should be

((T/T)a^(x/2))^2+((T/T)b^(y/2))^2=((T/T)c^(z/2))^2=

T^2 (c/T)^((((z/2)ln(c)/(ln(T))-1)/(ln(c)/(ln(T))-1)))2)

Rendered more readably


This is because . .