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Old 06-11-2009   #1 (permalink)
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Let's talk topology

This is nice subject to study. It also has important applications in many areas of applied mathematics, such as physics, chemistry, economics, meteorology and computer science. Probably others too.

Let me say this - you can think of this as a "tutorial" if you must, though I would rather you didn't. It's intended more as a "discussion platform". Also, it will be rather superficial - if more depth is wanted, I may be able to supply it. Finally - I am human (well almost), so I make mistakes. PLEASE correct me if you spot any. So here goes....

We start with a set S of points. We can, if we must, think of these points as being concrete objects like numbers, farmyard animals or the things in my garage, but it's best if we don't - better to keep them as abstract little buggers.

Now the powerset on S, generally written as \mathcal{P}(S), is the set comprising all the subsets of S.

Read that again: it's important to notice that, whereas S is a set of points, \mathcal{P}(S) is a set of sets of points. Ugh!

Also important is the fact that, by definition, every set has at least 2 subsets - S itself and the empty set \O.

So, for example, if S = \{a,b,c\}, then \mathcal{P}(S) = \{\{a\}, \{b\}. \{c\}, \{a,b\}, \{a,c\}, \{b,c\}, S, \O\}.

A topology T on S is defined as T\subseteq \mathcal{P}(S), satisfying the following axioms.

the intersection of any finite number of elements of T is in T;

union of an arbitrary number of elements of T is in T;

S \in T;

\O \in T

The "indivisible pair" S(T) is called a topological space.

Notice that one can always associate more than one topology to a given set, so let's dispose of two rather uninteresting topologies. The first is the case that T = \mathcal{P}(S) which is called the "discrete topology".

Even less interesting is the so-called "trivial" or "indiscrete" topology T = \{S,\O\}.

Now the elements (sets, recall) in T are called the open sets in S(T). The closed sets are found as follows.

Suppose A \subseteq S. Then the complement of A in S is simply all of S except A. This is often written as S\setminus A, but I will use A^c.

So, whenever A is open in S(T) id est A \in T, then A^c is closed in S(T).

Let's return to our simple example. Let S=\{a,b,c\} and suppose that T = \{\{a\}, \{b\}, \{a,c\}, \,S,\,\O\} \subsetneq \mathcal{P}(S) are the open sets in S(T).

Then \{a\}^c = \{b,c\},\, \{b\}^c= \{a,c\},\, \{a,c\}^c = \{b\},\, S^c = \O,\,\O^c = S are the closed sets in S(T).

Notice then that while \{b,c\} is closed and not open, and \{a\} is open and not closed, the sets \{b\},\,\{a,c\},\,S,\, \O are both open and closed and the set \{c\} is neither open nor closed. This generalizes.

Wow!
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