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Also important is the fact that, by definition, every set has at least 2 subsets - itself and the empty set .
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This is obvious if S is an empty set, but I was wondering if S contains say 2 points then you could say that S contains at leas 4 subsets, the ones above plus the ones including each point only.
Can't you also elaboarte it further then and say that every set S has 2+n! subsets where n is the number of points in S? I.e. 2 from

and

and then the possible order independent combinations of the elements/points in S...