Quote:
Originally Posted by Viv Pope tR = √(s2 + t2) Pythagoras This Pythagorean time-equation and the customary Einsteinian one, are inter-transformable. For instance, if it were necessary to express this same time-resultant, tR, in Einsteinian terms, then, since the relative velocity of the motion is the distance s travelled in the time tR (i.e., v = s/tR ), all we have to do is to substitute for s, in the Pythagorean equation, the equivalent vtR and then simplify, which produces the familiar (to physicists) equation: tR = t/√√(1 – v2/c2). Einstein |
This does work. If we observe someone from earth who is in a rocket. They are traveling half a light-year per year from our perspective then after five of our earth years...
By the lorentz transformations their clock has advanced 4.33 years as we observe it. They have traveled 2.5 light-years as we see it. We therefore have observed them:
It's basically the inverse of a normal Lorentz transformation rearranged a bit (you have to multiply time by velocity to get distance in light-distance) I'll show the math if anybody asks. I don't think this is significant except to say:
The Lorenz transformations can be derived from "Pythagorean" geometry. The constraints are that all axes are at right angles and light as a vector must follow the Pythagorean relationship to two of those axes. That is the consistent thing that makes the transformation possible. None of this was beyond Einstein. Nor do I think you can call it "relativity without Einstein" as the relationship relies on the consistent speed of light.
~modest
EDIT:
I will show the math as it's incredibly easier than I was picturing in my head:
Normal Transformation:

Multiply T' by the binomial and square:

So, yeah, not too much past Einstein's abilities I'd wager
Second edit: (I seem to have lost the ability to do basic algebra):
Starting with the more accurate transformation:

squaring both sides:

Rearrange:

Multiply by the binomial and rearange:

and you get:

Ok, I think that's right.