General Chem question!! HELP

somebody · 10-24-2005

Alright, before you read the problem just wanted to make things clear that the problem that i am goona give it to you is a advance REVIEW(advance for me atleast) problem in my book. SO dont think that i am trying to get my homework done here (had some problems in the past with the homework stuff so just want to make clear), its just a review problem before my midterm so it would be nice if you guys give me some good hints

or steps!!

what volume of 0.248 M CaCl2 must be added to 335 ml of 0.186 M KCl to produce a solution with a concentration of 0.250 M Cl-?

Easy for you but hard for me!

Jay-qu · 10-24-2005

ok, well if you look at the amount of mol and the volumes seperately

initially 0.335L and 0.0623mol
your other solution for every L has 0.496mol

and it has to equal 0.250M

now you could set up an equation

0.25 = n/V

0.25 = (0.0623 + 0.496V)/(0.335 + V) where V = volume added

following through to conclusion V = 87.2mL

I skipped a few steps setting up the equation and then solving it so if you dont understand just ask