| Re: Questions on HCl and H2SO4 reactions When examining a double displacement reaction, you must switch the cations and anions, forming two new products. Take the example that Jay-qu used:
NaCl + KNO3 --> NaNO3 + KCl
This reaction would in fact not take place at all. Note the products. Both of them are soluble, which means that the reaction would not take place. For a double displacement reaction, one of the products must be soluble, and one must be insoluble (precipitate).
This reaction would take place:
KI + Pb2NO3 --> KNO3 + Pb2I
The products are potassium nitrate (soluble) and lead iodide (insoluble)
Note: this rule works only in aqueous reactions.
I hope that helps!
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Last edited by Mercedes Benzene; 05-16-2006 at 07:01 PM.
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