Help with Moles

[Fantasian]

Questions:
1) Find the number of moles in potassium manganate(VII) used per titration
2)Calculate the number of moles of Fe in 250cm cubed of the solution
3) Given that the chemical forumula of Iron(II) sulphate is FeSO4 calculate the mass of iron(II) sulphate in the tablet
4) what is another way to determine the amount of iron in the tablet

Information:
The mass of an iron tablet can be found by dissolving it in dilute sulphuric acid and titrating against potassium manganate.

5Fe + MnO4 + 8H -> 5Fe + mn + 4H2O

potassium manganate solution - 0.00250 mol/dm(cubed)
25cm (cubed) of iron(II) solution
10cm (cubed) of dilute sulphuric

Titration resulted in a value of 9.55 ml

Help on these questions would be greatly appriciated, sorry for my Lack of chemistry knowledge he missed alot of lectures.

If the reply can be asap that would be great it's handed in, in 2 hours

[Mercedes Benzene]

Ooops. I could have helped you with it... but since you posted this yesterday, and it was due 2 hours from then, I suppose it doesn't matter.
If you still want the answers, I'll try to help you, but apparently here at Hypography we discourage giving answers to homework.

[UncleAl]

Start with a balanced equation:

1) Identify your redox-active centers.
2) Remove spectator ions.
3) Conserve charge flow with small integral multipliers
4) Insert the coefficients into to your original equation
5) Use H+, OH- and H2O to balance mass composition as needed.
6) Small intergral multipliers again, as needed, to have whole chemical species on both sides of the arrow. Verify there is no common integral factor throughout.

A one molar solution has one mole of solute in one liter of solution, or 1 mM/cm^3.