Newtonian Bowling

Originally Posted by CraigD

I made an additional code change to un-uglify it, eliminating the redundant calculations, posted the fixed code were the unfixed appeared in post #1,

If I understand correctly, the code box in post #1 is new and improved, so, get rid of the code I have been using, and plug-in the new and improved?

[CraigD]

Originally Posted by chendoh

If I understand correctly, the code box in post #1 is new and improved, so, get rid of the code I have been using, and plug-in the new and improved?

Yes – though “new and debugged” would be a better description.

Repeating the procedure you followed to load and save the original code do the job.

Though the bug doesn’t appear to affect many simulation runs of the “bowling alley”, it effects enough of them that you should mistrust results obtained from the old code.

All of life is a beta test …

Originally Posted by CraigD

Yes – though “new and debugged” would be a better description.

My apoligies, old slang....That belongs in the "Do you remember"
thread......
Now where's that scorecard?

[freeztar]

Originally Posted by CraigD

left all ten pins – a true “gutter ball”:

   c                               d
 
                               f
 
 
 
 
 
                   1
 
               2       3
 
           4       5       6
 
       7       8       9       a
 
   e
Sim T:0

   c                               d
 
 
 
 
 
 
 
                   1
                                  f
               2       3
 
           4       5       6
 
       7       8       9       a
 
   e
Sim T:1.25

   c                               d
 
 
 
 
 
 
 
                   1
 
               2       3
 
           4       5       6
 
       7       8       9       a
 
   e
Sim T:1.333333333333333343

I forgot the minus sign.
Let's try it again...

Ball mass=1.7
x=8.5
v=(-1.5,3)

[CraigD]

Originally Posted by freeztar

I forgot the minus sign.
Let's try it again...

Ball mass=1.7
x=8.5
v=(-1.5,3)

Very interesting – no ball contact with the 1 pin (nor, unfortunately between anything and the 1 pin). Left the 1, 8, and 10.

   c                               d

                                 f





                   1

               2       3

           4       5       6

       7       8       9       a

   e
Sim T:0

   c                               d







                   1
                         f
               2      3

           4       5       6

       7       8       9       a

   e
Sim T:1.220494506428849876

   c                               d







                   1

               2   3      f

           4       5       6

       7       8       9       a

   e
Sim T:1.520657330500272825

   c                               d







                   1
              2
               3         f

           4      5
                            6
       7       8       9       a

   e
Sim T:1.83928483584012753

   c                               d







                   1
              2

            3            f
          4
                  5
       7       8       9     6 a

   e
Sim T:2.110007673355126901

   c                               d







                   1
              2

            3            f
         4

       7       8  5    9       a

   e
Sim T:2.331230756545607822

   c                               d







              2    1

           3
                         f

        4
      7        8  5    9       a

   e
Sim T:2.462843202122834408

   c                               d







              2    1

          3

      4                 f

               8       9       a
     7
   e
Sim T:2.799182380347328782

   c                               d







             2     1

          3

      4                 f

               8       9       a

   e
Sim T:2.935230846449298945

   c                               d






             2
                   1
         3


     4                  f

               8      9        a

   e
Sim T:3.160594880905789525

   c                               d





            2

       3           1




                        f
               8               a
                     9
   e
Sim T:4.009338243279255224

   c                               d




            2

      3
                   1




                        f
               8               a

   e
Sim T:4.533009777017878759

   c                               d


           2




                   1




                        f
               8               a

   e
Sim T:5.828071327319384421

   c                               d







                   1





               8         f     a

   e
Sim T:7.677107475593590691

   c                               d







                   1





               8               a

   e
Sim T:10.64620043929137057

[freeztar]

OT, I was daydreaming and just thought of this type of game, but with billiards! It would be great fun to have a game in progress where whoever,whenever, can come along and take a shot. The winner would be the one who hits the most balls in the pockets. Of course, I have no idea how difficult this would be to simulate, but it doesn't seem like that far of a stretch from the bowling. Just an idea.

And with my favorite ball in hand (I call it "Force") I step up to the line, throw my arm back and then forward, and release...

Ball mass=1.7
x=8.5
v=(-1.25,3)

[CraigD]

Originally Posted by freeztar

OT, I was daydreaming and just thought of this type of game, but with billiards! It would be great fun to have a game in progress where whoever,whenever, can come along and take a shot. The winner would be the one who hits the most balls in the pockets. Of course, I have no idea how difficult this would be to simulate, but it doesn't seem like that far of a stretch from the bowling. Just an idea.

That shouldn’t be too hard. It would require a couple a new “bumper” body type, an easy addition.

The trick would be adding friction to the “ball” body type. An essential element of a pool game is that the balls eventually stop moving, which, of course, will never happen in a frictionless simulation. A simple uniform acceleration in the opposite direction of the ball’s velocity with a “stop” event at zero velocity should be enough for a reasonably realistic-looking simulation… Sounds like fun – I’ll see if I can do it tonight, or later this weekend

And with my favorite ball in hand (I call it "Force") I step up to the line, throw my arm back and then forward, and release...

Ball mass=1.7
x=8.5
v=(-1.25,3)

Good adjustment – it took out the 1 pin. Left the 4, 7, 8, and 10

   c                               d

                                 f





                   1

               2       3

           4       5       6

       7       8       9       a

   e
Sim T:0

   c                               d







                   1

               2       3 f

           4       5       6

       7       8       9       a

   e
Sim T:1.4369955981006127

   c                               d







                   1
                      3
               2         f

           4       5       6

       7       8       9       a

   e
Sim T:1.454533916821456982

   c                               d







                   1
                    3
               2

           4       5   f

       7       8      9      6 a

   e
Sim T:1.960168411703652255

   c                               d







                   1
                   3
               2

           4       5  f

       7       8               a
                      9
   e
Sim T:2.201176293766480755

   c                               d






                   1
                   3

               2

           4       5 f

       7       8               a
                      9
   e
Sim T:2.294675071470479173

   c                               d






                  1

                  3
               2
                  5
           4         f

       7       8               a
                      9
   e
Sim T:2.34579719391154908

   c                               d






                  1

                  3
               2
                  5
           4         f

       7       8               a

   e
Sim T:2.380138884856690461

   c                               d






                  1

               3
               2
                5
           4
                   f
       7       8               a

   e
Sim T:3.070475142422318752

   c                               d





                  1

             3

              2
               5
           4

       7       8  f            a

   e
Sim T:3.37438285889799684

   c                               d




                  1


        3   2


              5
           4

       7       8               a

   e
Sim T:4.631445773150469158

   c                               d


                  1



          2




           4 5

       7       8               a

   e
Sim T:5.779230158156360029

   c                               d


   2








           4

       7 5     8               a

   e
Sim T:8.900663434423030335

   c                               d











           4

       7       8               a
         5
   e
Sim T:9.192619205512951801

   c                               d











           4

       7       8               a

   e
Sim T:10.56154117855066968

[freeztar]

Originally Posted by CraigD

That shouldn’t be too hard. It would require a couple a new “bumper” body type, an easy addition.

The trick would be adding friction to the “ball” body type. An essential element of a pool game is that the balls eventually stop moving, which, of course, will never happen in a frictionless simulation. A simple uniform acceleration in the opposite direction of the ball’s velocity with a “stop” event at zero velocity should be enough for a reasonably realistic-looking simulation… Sounds like fun – I’ll see if I can do it tonight, or later this weekend

Somehow I knew you'd be into the idea.
I have some other ideas for it as well (friction is a must of course). Since numbered balls are not needed (assuming it's just a game of try to hit a ball in), perhaps the symbology can be changed a bit in the ASCII? Perhaps an "x" for the cue ball and an "o" for all the other balls. It would be easier to estimate angles, imo. It might also be easier to create a table with only four pockets (one in each corner).
Cheers for your efforts!

Good adjustment – it took out the 1 pin. Left the 4, 7, 8, and 10

Well my goal was accomplished because I wanted that 1 pin. Unfortunately, I'm still not getting it quite right. I think my ball mass is too low so it's not having much movement after a few encounters with "pins" (at least from what I can judge by the snapshot positions). So this time:

ball mass=1.8
x=8.5
v=(-1.25,3)

[CraigD]

Originally Posted by freeztar

Somehow I knew you'd be into the idea.
I have some other ideas for it as well (friction is a must of course). Since numbered balls are not needed (assuming it's just a game of try to hit a ball in), perhaps the symbology can be changed a bit in the ASCII? Perhaps an "x" for the cue ball and an "o" for all the other balls.

It’s very easy to add different interfaces to the core simulator code, so minor changes to the ASCII are no problem. With a bit of html ingenuity, it should be possible to render some simple graphics. One of my key ambitions is to write a generic GIF or similar graphics format renderer in ANSI-standard MUMPS – I’ve been getting “rumors from the top” that I may soon get a chance to do this at work

Well my goal was accomplished because I wanted that 1 pin. Unfortunately, I'm still not getting it quite right. I think my ball mass is too low so it's not having much movement after a few encounters with "pins" (at least from what I can judge by the snapshot positions). So this time:

ball mass=1.8
x=8.5
v=(-1.25,3)

The slight ball mass increase was significant. Only the 10 pin left – and the 6 came close to getting the 10 after its collision with the ball.

   c                               d

                                 f





                   1

               2       3

           4       5       6

       7       8       9       a

   e
Sim T:0

   c                               d







                   1

               2       3 f

           4       5       6

       7       8       9       a

   e
Sim T:1.4369955981006127

   c                               d







                   1
                      3
               2         f

           4       5       6

       7       8       9       a

   e
Sim T:1.45533533558412979

   c                               d







                   1
                    3
               2

           4       5   f

       7       8      9      6 a

   e
Sim T:1.951896949917645616

   c                               d







                   1
                   3
               2

           4       5  f

       7       8               a
                      9
   e
Sim T:2.185452411139611041

   c                               d






                   1
                   3

               2

           4       5 f

       7       8               a
                      9
   e
Sim T:2.316420653730639343

   c                               d






                  1

                   3
               2
                  5
           4         f

       7       8               a
                      9
   e
Sim T:2.322727638320321595

   c                               d






                  1

                  3
               2
                  5
           4         f

       7       8               a

   e
Sim T:2.359013726995956065

   c                               d






                  1

               3
               2
                5
           4

       7       8   f           a

   e
Sim T:3.083658749841490086

   c                               d





                  1

              3

              2 5

           4

       7       8  f            a

   e
Sim T:3.334724309435983317

   c                               d





                  1

             3
              2

               5
           4

       7      8  f             a

   e
Sim T:3.61339115351040725

   c                               d




                  1


          3
            2

               5
           4
              8
       7                       a

   e
Sim T:4.324471978605371914

   c                               d


                  1



      2




           4  5
            8
       7                       a

   e
Sim T:6.130134771817362993

   c                               d

                  1



     2





           8
              5
       7                       a

   e
Sim T:6.776911083059362577

   c                               d
                  1









          4

           8  5
       7                       a

   e
Sim T:7.529689810447353354

   c                               d










          4

          8
       7     5                 a

   e
Sim T:8.891296845722150753

   c                               d









         4


        8
       7                       a

   e
Sim T:10.54110253531142023

   c                               d









         4


        8
      7                        a

   e
Sim T:10.75490125692885145

   c                               d






       4




        8

                               a

   e
Sim T:17.00727985720945931

   c                               d










      8


                               a

   e
Sim T:32.2849296346853025

   c                               d













                               a

   e
Sim T:63.71596461652395272

[freeztar]

That was close!

Now it is a matter of determining whether small changes will be able to hit the ten, or whether it will offset the other interactions in a negative manner. I'm hoping that an increase in vertical velocity will create a slightly different angle (and of course speed) resulting in a guttered 10 ("a") with no significant differences from last throw expressed throughout the rest of the pins' fates.

ball mass=1.8
x=8.5
v=(-1.25,3.1)