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Old 06-12-2008   #1 (permalink)
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Intergration

Hey guys

I have a peice of homework to do from college
i have an equation in the format:
a((bx^n)+cx)
and i need to intergrate it.

Intergrate as in reverse of differentiation aka antiderivative.

many thanks to anyone who can help.

Last edited by pigeon_soup; 06-12-2008 at 02:39 PM.
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Old 06-12-2008   #2 (permalink)
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Re: Intergration

It would be helpful if you gave us some more information. What equation are you trying to integrate? What steps have you taken to integrate it? Is there a particular step, technique, or rule that's giving you trouble?

For posting equations you can use latex which is explained and discussed in this thread:
http://hypography.com/forums/physics...th-v2-0-a.html

-modest


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Old 06-12-2008   #3 (permalink)
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Re: Intergration

Hello, and welcome to Hypography.

Can you show what you have worked out so far?


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Old 06-12-2008   #4 (permalink)
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Re: Intergration

ok here goes :S

\frac{dy}{dy} = \fract {9}{32} (x^2 -4x)
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Old 06-12-2008   #5 (permalink)
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Re: Intergration



I need to get this to the format y= blah blah blah using intergration.
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Old 06-12-2008   #6 (permalink)
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Re: Intergration

ok,

\int \frac{9}{32}(x^2 - 4x)dx


What do you think your first step would be?


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Last edited by modest; 06-12-2008 at 04:45 PM. Reason: latex
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Old 06-12-2008   #7 (permalink)
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Re: Intergration

It depends on your preference as to what the first step would be. You can either choose to put 9/32 "outside" of the integral, which is one of the rules of integrating or you can distribute the 9/32 so that you have 9/32 * x^2 -9/8*x. Now with either step done, we know that when we are integrating a linear combination of continuous function, we can integrate each function separately. So if you performed the "first step" the second way, then you would integrate 9/32 * x^2 and -9/8*x separately. If you have a polynomial of degree n, for any natural n, so x^n, then it's integral is x^n+1/(n+1).

Here's a page that gives detailed explanations

Indefinite Integration of Polynomials


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Old 06-12-2008   #8 (permalink)
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Re: Intergration

and don't forget indefinite integration produces a constant that gets added onto the function you just integrated.


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