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Not Ranked : +0 / -0 0 score Re: Calculus Help Needed-Vesica Piscis Thread-Post#11 since the thingy involves with 2 circles of radius of 2...
lets set up equations of these 2 circles,
first one= x^2 + ( y-1)^2 = 4
second one= x^2 + (y+1)^2 = 4
solve for the system, and find the intersections.
so, the equation of the top curve of that "thing" would be the second circle, x^2 + (y+1)^2 = 4,
solve for y, y= sqrt (4 - x^2)-1
area would be the integral of pi*(y^2)dx---from (pi*r^2)--which is, pi*(sqrt (4 - x^2)-1)^2 dx using the intersections as bounds.
---------------- I have mistaken, apologized, and taken the consequences. My only regret, was for how I was bothered by the unchangable. |