I’ll take a shot at the question. I’m not capable of the formal math of it, but think I can outline photon-atom interaction without it.
Let me begin by filling in some of what I think are key details needed for understanding in Little Bang’s original description
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Originally Posted by Little Bang
I have two hydrogen atoms on a collision course at some low velocity. When the fields of each atom …
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Here, we need to consider what we mean by “the fields of each atom”.
In particle physics, force fields (except for gravity) are the result of exchanges of particles in the
boson family by particles in the
fermion family. In this example, the bosons are
photons of magnetic force, exchanged mostly between the two electrons of the hydrogen atoms, but also, to a smaller net effect, between the two protons.
Protons, or more properly, their constituent
quarks, are also exchanging photons of magnetic force with electrons. Because we can’t measure these photons any way but by their effect on the protons and electrons, they’re called virtual. Precisely how many and when they’re exchanged is a matter of probability, not certainty – “quantum weirdness”, but very physically real.
The major thing all this virtual photon exchanging accomplishes is changing the momentum of the most massive parts of the atoms, their protons – or more properly, their most massive constituents, which are not their quarks, but the boson exchanged by the quarks,
gluons.
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… get to some point in their approach each electron jumps to a higher energy level …
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In the process of this, the electrons will be placed in a “higher”, which is to say, less statistically likely,
”orbit”. These orbits are due to the exchange of magnetic force photons with the quarks of their protons, and are further constrained by the quantum wave functions of the electrons. These wave functions essentially require that the circumference of the electrons’ orbits be an even multiple of their
de Broglie wavelength, causing these orbits to be discrete, or “quantatized”. The electrons then return to their lower, “ground” orbits. In so doing, they emit real photons of radiation. A hydrogen atom, or a system of two hydrogen atoms, can emit only photons of various discrete frequencies. Since this example states that the atoms were colliding at a low speed, we can assume that the electrons will have been raised to orbits not much greater than their ground states, and all these photons will be fairly low energy, in the infrared range.
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… and then as they began to separate each electron falls back to the lower energy level …
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There’s no requirement that the hydrogen atoms separate. They can remain close together, with nearly all of the kinetic energy of their former relative motion converted to photons of infrared radiation. This is the process by which a warm hydrogen gas, and eventually, a liquid and solid, cools, and can continue until the atoms near
absolute zero temperature, and their relative motion is too low to raise many electrons above their ground orbits.
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… and creates a complete infrared waveform with a crest and trough. …
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The electrons just emit discrete photons of an energy exactly equal to the difference in potential energy between their higher, “excited” orbit, and their ground orbit. The wave nature of this photon is inherent in it, requiring no special timing on the part of the electron or the other particles interacting with it.
If you research the details of the above, the degree of my simplification of my explanation will become apperant. In particular, you’ll see I fudged considerably with the idea of the ground state orbit of an electron, because hydrogen emits infrared photons only for transitions to it’s second-from lowest orbital and above (for example, for
Paschen series transitions to its 3rd orbital).
As Qfwfq notes, actually working out the details of what I’ve outlined would be a very complicated calculation. You’d have to statistically account for a literally infinite number of discrete exchanges of virtual photons, and many other difficult details. As many physics wags have noted over since
Dirac and others first described this stuff, the only simulator really adequate for these sorts of calculations is the universe itself

I hope, though, I’ve left Little Bang with a different opinion than
Quote:
Originally Posted by Little Bang
We do not have an understanding of the steps that produce a photon. The equations work beautifully but they do not paint (the picture is worth a thousand words). In my opinion we are missing an important piece of information about the relationship between the electron and proton. What that might be I don't know. I hope that someone somewhere will answer that question before I die.
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The understand he seeks exists, I think, even if the exact mathematical mechanics of it are complex beyond practical calculation, and even approachable only by a small number of superbly educated and practiced physicists.
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