Welcome to hypography, tmm35!

Quote:
Originally Posted by tmm35
Does anyone know the relative speeds and trajectory of possible MBH created by cosmic rays. If their argument for safety is that cosmic rays may create them and we are still here then should they not mimic the conditions of a cosmic ray collision in LHC rather.
|
The
LHC’s most energetic collisions – those involving lead nuclei – are a bit over

eV (1150 TeV). It’s max for a proton (hydrogen nuclei) collision is a little over

eV (14 TeV).
Cosmic rays, the highest energy kind which are mostly protons and helium nuclei – have been detected with energies over

eV – that is, over 100,000 times as energetic as the LHC can create.
So the LHC
can’t mimic the highest energy cosmic ray collisions, because it’s not powerful enough. Though it’s the most powerful accelerator made by humans, it’s still puny by the standards of the cosmos – though much more conveniently located to its detectors.
As for trajectories – ie angle of impact – any other than a head-on, 180°, simply results in a lower-energy collision, so are not a significant factor.
Though physicists usually don’t, you can convert from a particle energy to a velocity by algebraically manipulating the
mass dilation formula

into
The mass of a proton is about

eV (938 MeV), So the speed of a

eV proton is about 0.999999995 c. The mass of a lead atom is about 200 times (208.76) that of a proton, so a

eV lead nucleus has about the same speed as a

eV proton. The speed of a

eV proton is about 0.99999999999999999999995 c (if I haven’t miscounted a 9 – now you can see why physicists usually prefer to use the energies of high-speed particles, rather than their speeds.

----------------
Moderator: Computers and Technology; Medical Science; Science Projects and Homework; Philosophy of Science; Physics and Mathematics; Environmental Studies
