Right angled triangle combinations(3,4,5....)

Roadam · 06-09-2006

We all probably know that combination. Is there any other combination than this to fit into a^2+b^2=c^2? Other than its multiples(6,8,10) of course.

cwes99_03 · 06-09-2006

Quote:

Originally Posted by Roadam

We all probably know that combination. Is there any other combination than this to fit into a^2+b^2=c^2? Other than its multiples(6,8,10) of course.

You are asking about square roots. Forget the whole triangle (thought the question remains the same whether you think of it as a triangle or not).

You are asking if the sum of the squares of any two numbers, equals the square of another number.

Do some number crunching, see if you can find any combinations. 25^2-24^2-=?^2.

cwes99_03 · 06-09-2006

Wow, just pulled that out of my . Must have seen it before.

GAHD · 06-09-2006

hehe, wanna see that math screw up?

Assume A and B are both 1 ...

TheBigDog · 06-09-2006

Quote:

Originally Posted by Roadam

We all probably know that combination. Is there any other combination than this to fit into a^2+b^2=c^2? Other than its multiples(6,8,10) of course.

Try this on for size. There is also some discussion in the Katabatak thread. Or look up primitive right triangles on Wiki. There are an infinite number of unique integer right triangles.

Bill

UncleAl · 06-09-2006

Draw a circle on a piece of graph paper with its center at the origin. Every point on the circle satisfies the relationship x^2 + y^2 = (radius)^2. Pick a radius, pick a point, then read off its coordinates.

Tim_Lou · 06-09-2006

these triples are in the forms of:
$a=2xy$
$b=x^2-y^2$
$c=x^2+y^2$
using these equations, you can generate these triples:
example:
let x=7, y=5
a=2*5*7=70
b=49-25=24
c=49+25=74

$24^2+70^2=74^2$

you can prove it yourself:
$a^2+b^2=(2xy)^2+(x^2-y^2)^2=c^2$