Relative Quantum Charge Dyanamics

arkain101 · 06-13-2006

Interesting posts Kick.

Quote:

I like to think about a body orbiting about another body that is said to be at "rest". This will be such that it is a three body system. Q, is the body that is our rest reference frame. q_1 is said to orbit relative to Q, such that it has time, t, and at a radius, r, of 3. q_2 is said to orbit relative to Q, such that it has time, t', and at a radius, r', of 4.

Time is measured in frequency of the orbiting bodies relative to the "rest" body.

I would like to hear people's thoughts.

I do not think you will be measuring time (in some fundamental form).

You said,

Quote:

However I will note that implies that time is implicitly a property of interaction

The 2 objects orbiting a rest body is an 'interaction'.

The 2 objects orbiting that body would definatly measure something, and I assume it would bring forth a constant of sorts.

Its late. However I thank you for your detailed posts. I've got much to learn in the maths.

KickAssClown · 06-13-2006

Think of it in rotations. If q1 rotates a circumferance of $2\pi r = 2\pi 3 = 6\pi$ , it will complete 1 orbit "before" q2 will.
$6\pi/1 = 18.8\overline{4}$

$2\pi r' = 2\pi 4 = 8\pi$
$8\pi/1 = 25.13\overline{2}$

by a factor of $\Delta 25.13\overline{2}-18.8\overline{4} = 6.29\overline{2}$
from the perspective of Q relativitely q_2 will seem to move slower to q_1.

KickAssClown · 06-13-2006

Ok some explaining needs to be done I think.

OK Basic Premiss is that all matter is charge, and that all matter breaks down into two patterns of charge.
Exclusive
Photonic

A matter pattern is either Magneticly, Neutrally, or Electrically biased.
A matter pattern is a vector of n bodies of charge, such that the number of configurations possible are: n!.
We can use Minskowski space to represent the state of the Charge-Space vector.
We can use Orbital Mechanics to calculate the configuration of the points of charge within the Minskowski space, such that the outcomes would be the probability of a given state at a given time.

Oh and as an answer to earily. My theorm by requirement shouldn't deviate much from the standard theorys of General relativity, and Quantum Mechanics, and should be in majority inclusive of all Standard Theory Phenomena. Further the Mathematics, and equations should be universally applicable from the Macrocosmos to the Microcosmos. All things should be governed by Generally Relative Phenomena as well as Quantum phenomena.

I would like to call this theory: Relative Quantum Charge-Space Dynamics.

This Theorm must agree with all given physical laws. With at it's heart the collected body of Physical Laws.

It introduces some relatively new laws:

The Laws of Dynamism:
[1]All is Change
[2]All is Impermanent
[3]All is Transitory
The Laws of Duality:
[1]For each state their is an equal and opposite state.
[2]All dualities have three properties, positive, balanced, and negative.

I am trying to think of more so I will post in a bit, once I have a good grasp on how to state and what to state here.

Turtle · 06-13-2006

Quote:

Originally Posted by KickAssClown

Ok some explaining needs to be done I think.

It introduces some relatively new laws:

...
The Laws of Duality:
[1]For each state their is an equal and opposite state.
[2]All dualities have three properties, positive, balanced, and negative.

I am trying to think of more so I will post in a bit, once I have a good grasp on how to state and what to state here.

These aren't new concepts or nearly as developed as similar definitions put forward by Buckminster Fuller for qualifying a Unified Field.
http://www.rwgrayprojects.com/synerg.../plate09z.html

arkain101 · 06-13-2006

Right turtle, that is an interesting fellow with very great ideas.

Turtle its new, the cake may not be so new , but the icing and cherry on top is very new. It is to conjoin everything.

Next post I am listing the wack of postualted principles I've developed that the theory model backs up.

KickAssClown · 06-14-2006

Properties of the Fundemental particles, Charge Quanta:
$E = 1, spin = 1, parity = +$
$B = 1, spin = 1, parity = -$
$\gamma = (1, 1), spin (1, 1), parity (+,-)$

How does one describe a relative co-ordinace system? Such that body is always (x, y, z) = (1, 1, 1) to itself.

$\begin{bmatrix}1 & x, y & x, z & x, t \\ y, x & 1 & y, z & y, t \\ z, x & z, y & 1 & z, t \\ t, x & t, y & t, z & 1\end{bmatrix}$
$\begin{bmatrix}+ & - & + & - \\ - & + & - & + \\ + & - & + & - \\ - & + & - & +\end{bmatrix}$

Lorentzian Transformation Matrix:
$\begin{bmatrix} c t_1 \\x_1 \\y_1 \\z_1 \end{bmatrix} = \begin{bmatrix} \gamma & - \beta \gamma =& 0 =& 0\\ - \beta \gamma =& \gamma =& 0 =& 0 \\ 0 =& 0 =& 1 =& 0 \\ 0 =& 0 =& 0 =& 1 \\ \end{bmatrix} \begin{bmatrix} c t_2 \\x_2 \\ y_2 \\ z_2 \end{bmatrix}=$

Such that:
$\frac{\begin{bmatrix} c t_1 \\x_1 \\y_1 \\z_1 \end{bmatrix}}{\begin{bmatrix} c t_2 \\x_2 \\ y_2 \\ z_2 \end{bmatrix}} = \begin{bmatrix} \gamma & - \beta \gamma =& 0 =& 0\\ - \beta \gamma =& \gamma =& 0 =& 0 \\ 0 =& 0 =& 1 =& 0 \\ 0 =& 0 =& 0 =& 1 \\ \end{bmatrix} =$

Maxwell's Equations with Magnetic Monopoles:
$\nabla \cdot \mathbf{E} = \frac{\rho_e}{\epsilon_0}$
$\nabla \cdot \mathbf{B} = \mu_0 c \rho_m$
$\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t} - \mu_0 c \mathbf{J}_m$
$\nabla \times \mathbf{B} = \frac{1}{c^2} \frac{\partial \mathbf{E}} {\partial t} + \mu_0 \mathbf{J}_e$

Quote:

Originally Posted by Inaccurate, Needs further examination

It has come to my attention through careful scrutiny and the help of a friend of mine by the name of Mack, that it can be expressed that:
$q_1, q_2, r_1, t_1$
where
$q_1$ is the net charge of a given body, which is the rest frame for this interaction.
$q_2$ is the net charge of the body in motion about $q_1$ .
$r_1$ is the distance to $q_2$ from $q_1$ .
$t_1 = 2\pi r_1$
These can be given the relationship of, if electromagnetic in nature:
$|F| = k_C \frac{|q_1| |q_2|}{r_1^2}$

In our example we will assume for now that $q_1$ is 1 electric quanta and $q_2$ is 1 magnetic Quanta at a quantum distance, $r_1$ , from one another of 1. Now if we introduce a second state of particles into this, thus that we get:
$q_3, q_4, r_2, t_2, r_3, t_3$
Where:
$q_3 = 1$
$q_4 = 1$
$r_2 = 1$
$t_2 = 2\pi r_2$
$r_3 = n$ which is the distance of this system, $E_2$ , to the other, $E_1$ . As usual it must be a whole, non-zero, non-negative number.
$t_3 = 2\pi r_3$
So that:
$E_1 = q_1q_2r_1^2/t_1^2$
$E_2 = q_3q_4r_2^2/t_2^2$

then the sum of the states should be such that:
$\sum_{i=E_n}^{n}E_n = E_1+E_2+E_3+E_{...}+E_n$

KickAssClown · 06-14-2006

E is Electric
B is Magnetic
S is Strong
W is Weak
G is Gravity

$F_E = q*E$
$F_B = qv * B$

The force between two magnetic monopoles is as follows:

$F={{m_1m_2}\over{\mu r^2}}$

where

F is force (SI unit: newton)
m is pole strength (SI unit: weber)
μ is the permeability of the intervening medium (SI unit: tesla meter per ampere)
r is the separation (SI unit: meter).

arkain101 · 06-14-2006

right on Kick,

I am impressed, whether this is correct or not. You know what your up to.

I've been busy, but I am going to look over everything you been posting. Sweet time.

KickAssClown · 06-14-2006

I would like to note that the photon is either a double or triple helix, such that if it is viewed head on and displayed on a 2d plane it's orbits would look like circle, however viewed Isometricly it's would look like two or three spirals, like two or three corkscrews.

This relates beatifully to the Fibonacci Sequence and the Golden Ratio.

KickAssClown · 06-14-2006

I've been contemplating the $q_E = q_B^{-1}$ relationship, as it gave me quite a pause, but I believe I have it now, it's all in the property of chirality.

such that q_E will be redesignated q_t, and q_B will be redesignated, q_f.
such that their properties shall be equal but opposite in chirality.
$q_t, q = 1, spin = 1, chirality = +, r=1, t=2\pi r'$ (right handed)
$q_f, q = 1, spin = 1, chirality = -, r=1, t=2\pi r'$ (left handed)
such that:
$\sum_{i = m}^{n}q_t^m = q_t^m + q_t^{m+1} + q_t^{m+2} + ... + q_t^{m+n}$
$\sum_{i = o}^{n}q_f^i = q_f^o + q_f^{o+1} + q_f^{o+2} + ... + q_f^{o+n}$
$\sum_{i = m, j = o}^{n}q_t^i/q_f^j = q_t^m/q_f^o + q_t^{m+1}/q_f^2 + q_t^{m+2}/q_f^{o+1} + ... + q_t^{m+n}/q_f^{o+n}$

Relative Quantum Charge Dyanamics

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