Playing with Heisenberg's uncertainity principle

[ronthepon]

I'll get to the point.



Or


Where m is the mass of the particle under consideration.

Now let the maximum value of be equal to Agreed?

So, minimum value of will be given by


Correct?

Can we take this as the... say observation radius or something?

And lets apply the constants.

I got by using Log tables.

There is a problem. Using the masses of neutrons and protons here, I get values at about , which is about a hundred times the size of the atomic nucleus.

Can somebody help me get this?

[ronthepon]

By the way, I have no idea how the uncertainity principle was derived or reached.

[UncleAl]

1) If you are hard by lightspeed the observed mass is no way near the rest mass.

2) Momentum is not mv except in Newtonian physics. Momentum is a conserved four vector.

3) Look up the Lamb shift for hydrogen and then the Lamb shift for U(91+). Relativistic corrections matter.

[ronthepon]

to number one, I'ts the uncertainity that's c, and we have no idea at all about what's the true speed anyway...

Meanwhile I'll be checking out the directions you gave...

[Qfwfq]

Never mind Unk's manners Ron.

The expression for momentum is:



and I'm sure you can easily check that it isn't upper bound as v approaches infinity.

Your idea was essentially based on p having the upper limit mc, and thus alsop, but this isn't so because the denominator is infinitesimal.

[ronthepon]

Thanks a lot, Qfwfq, that clears it all up.