Of course, in your case Mohit a and d are both 1, so we get n(n + 1)/2. For n = 100 we get 50*101.
Erasmus' post makes it easier to understand why, and you can imagine stacking little squares. Draw one square beside a stack of two and then a stack of three etc. You get half of a big square of little squares, including the diagonal. The big square would be n little squares on each side, try working out exactly how many little squares there are using what Erasmus said.
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Inutil insegnŕ al mus, si piart timp, in plui si infastiděs la bestie.
Mohit Pandey haven't u read CBSE X maths .I can do these in a second ,i think u are in IX or VIII otherwise u have known it.
actually they form the basic of A.P (what we call arithmetic progression),a very interesting story of gauss is related with it.
Now my question on sequences -:
a polygon with 100 sides have how many diagnols?
u can use either logic or A.P formulae.
I AM BACK !
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Where there is the end of science,from there the spirituality starts