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Old 08-30-2006   #1 (permalink)
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Lightbulb Sequence and series trivia

Hello Hypographites,
Here is a question for all --Find out the total of 1 to 100? Give the method or formula used.
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Old 08-30-2006   #2 (permalink)
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Re: Addition

Quote:
Originally Posted by Mohit Pandey
Hello Hypographites,
Here is a question for all --Find out the total of 1 to 100? Give the method or formula used.
Divide it into 50 pairs of 101. (1+100, 99+2,3+98... etc). Hence, the sum is 50*101= 5050.
-Will
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Old 08-30-2006   #3 (permalink)
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Re: Addition

101*50

It can be worked out for the sum of numbers raised to any power but I haven't time to say more right now...


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Old 08-30-2006   #4 (permalink)
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Lightbulb Re: Addition

Quote:
Originally Posted by Erasmus00
Divide it into 50 pairs of 101. (1+100, 99+2,3+98... etc). Hence, the sum is 50*101= 5050.
-Will
How did you find out? Any clue.
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Old 08-30-2006   #5 (permalink)
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Re: Addition

You don't know Arithmetic Progression?

The formula states:



If I still fail to light a bulb,

S: is the sum you want.

a: in the first term of the series

d: 'common difference' is the difference between two succesive numbers in the series.

n: is the number of terms you wish to add in all.

The method Erasmus00 mentioned was first used by Gauss(?), the person who developed the whole concept as a kid.


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Last edited by ronthepon; 08-30-2006 at 09:18 AM..
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Old 08-31-2006   #6 (permalink)
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Re: Addition

Of course, in your case Mohit a and d are both 1, so we get n(n + 1)/2. For n = 100 we get 50*101.

Erasmus' post makes it easier to understand why, and you can imagine stacking little squares. Draw one square beside a stack of two and then a stack of three etc. You get half of a big square of little squares, including the diagonal. The big square would be n little squares on each side, try working out exactly how many little squares there are using what Erasmus said.


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Old 09-09-2006   #7 (permalink)
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Cool Re: Addition

Mohit Pandey haven't u read CBSE X maths .I can do these in a second ,i think u are in IX or VIII otherwise u have known it.
actually they form the basic of A.P (what we call arithmetic progression),a very interesting story of gauss is related with it.

Now my question on sequences -:
a polygon with 100 sides have how many diagnols?

u can use either logic or A.P formulae.


I AM BACK !


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Old 09-12-2006   #8 (permalink)
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Re: Addition

Quote:
Originally Posted by ronthepon
You don't know Arithmetic Progression?

The formula states:



.
I think this formula is wrong ronthepon. The formula should be IMO



because the formula for the sum of an arithemtic series is given by (n/2)(t1 +tn) where tn = (t1 + d(n-1)) so I just think you missed an a

I apolagize in advance if im wrong :P
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Old 09-13-2006   #9 (permalink)
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Question Re: Addition

Quote:
Originally Posted by BrainForce
Now my question on sequences -:
a polygon with 100 sides have how many diagnols?

u can use either logic or A.P formulae.
Can anyone help me in solving this question?
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Old 09-13-2006   #10 (permalink)
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Re: Addition

See,you havew got to find a pattern ,a pattern which is followed by each polygon ,once u get the pattern nothing can deter u from getting this answer.

don't be dependent on formulae,I myself did this question correctly in class VII and used only logic and no formulae.


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