the jet propulsion with closed combustion type

[DFINITLYDISTRUBD]

[QUOTEYour discription is interesting. I think no matter how intereting it is, as long as it is high efficient and light-weight,realiable; comprehensively good, we should try.][/quote]

Good ol OPTIMISM! (Gotta love it! )

I've currently got two engines (one on the cart-one in my garage) one cart.
I have an aprox. 1Ltr. fuel tank which on average runs my cart for about 12 min. For fuel I use a mix of old motor oil 1 gal .5 gal gasoline .5 gal diesel and three gals kerosene (premixed in a 5 gal can) . The entire cart weighs aprox 200 lbs with my big-bum in it total weight aproaches 380 and flat out I've attained top speeds approaching 45 mph.

As for the engine in the garage I'm getting a little affraid to run it. IN my attempts to lighten it things are getting iffy!

[qumf]

Originally Posted by DFINITLYDISTRUBD

Good ol OPTIMISM! (Gotta love it! )

I've currently got two engines (one on the cart-one in my garage) one cart.
I have an aprox. 1Ltr. fuel tank which on average runs my cart for about 12 min. For fuel I use a mix of old motor oil 1 gal .5 gal gasoline .5 gal diesel and three gals kerosene (premixed in a 5 gal can) . The entire cart weighs aprox 200 lbs with my big-bum in it total weight aproaches 380 and flat out I've attained top speeds approaching 45 mph.

As for the engine in the garage I'm getting a little affraid to run it. IN my attempts to lighten it things are getting iffy!

I don’t study your material carefully because their characteristics or descriptions aren’t detailed. I don’t think the materials are fit to make the jet. The material can be fabricated as prototype to show the mechanical motion.
To implement this jet successfully, you must solve some difficulties: how to mix the fuel and air uniformly, how to ignite mixture gas quickly and reliable; how to design the flow pipe for high efficiency. You also need calculate: what frequency can it get? What current capacity do it has? How much is the push force? You must calculate something and do some experiment first. otherwise if previously you plan to let it fly but without the designed result, you may negate my idea.
After these preparation, even if you didn’t get the designed result at first, you easily to find and solve the problem.
Maybe you machine can work normally but it can’t fly, it is possible that the machine didn’t burning out enough fuel per second to provide enough force.

[DFINITLYDISTRUBD]

how to mix the fuel and air uniformly, how to ignite mixture gas quickly and reliable; how to design the flow pipe for high efficiency. You also need calculate: what frequency can it get? What current capacity do it has? How much is the push force? You must calculate something and do some experiment first. otherwise if previously you plan to let it fly but without the designed result, you may negate my idea.

otherwise if previously you plan to let it fly but without the designed result, you may negate my idea. Huh??wuh??? I don't get it. Old idea...been done many times before....I've just been refining it!

With regards to the rest^ sitting in front of a computer doing calculation after calculation is for scientists and people that love to do math! There are those of us that simply take basic mechanical principles and a basic understanding of realworld physics and use this knowlege to make gadgets for our own entertainment. (ie jet powered go-carts, "burp jet" bikes (pulse jet), electric superchargers and other performance goodies for road vehicles. etc)

Have you ever modified an automotive A/C system to provide additional cooling from an intercooler?

I have with decent results, and I didn't do any fancy math or follow any fancy formulas. I simply took known facts, an understanding of how A/C systems work and an assortment of "spare" components from previous trucks I've owned and put the pieces together. Result one cold intercooler!

I have 20 years of automotive and diesel, 20 years of electronics, 15 years of hydraulics, 20 years metal working, and 15 years of agricultural/industrial equipment repair/overhaul experience and these are all I need. The day I need to monkey around with calculations and formulas is the day I hang up my tools and call it quits...I design and build for fun!

[qumf]

Hi ,DFINITLYDISTRUBD:

I am sorry I can't be deside you,otherwise I explain detailed or I will help you do my best.

Your experience is good to manufacture the jet. maybe nearly enough. But you hasn't enough ability to design and calculate it. however it is nessary to made a new thing,It isn't that we are imitate something.

You should study Engineering Thermodynamics. or ask sb else to calculate it refer what I said before.

Though the jet is simple,after it is jet engine on the aeroplane!

what is "A/C system " you said?

Best regards

[qumf]

Hi,DFINITLYDISTRUBD

maybe I didn't understand you very well.
While you make the model of the jet, I hope the components are distributed as the illustration I attached before. I have thought the construction for a long time.
I would like to do my best to answer your questions about the details in my design that I haven't mentioned.

Best regards

[qumf]

I have analyzed the efficiency of two kinds of jet engines in theory. What is the actual efficiency of the new jet? While analyzing the efficiency in theory, the efficiency of the compressor and blower is 100%. Actual efficiency of compressor is lower much, about 70%. The blower’s efficiency is higher than the compressor’s. As to the current jet, after combustion a lot of gas energy that can be utilized is absorbed by the turbine for compressor. In the new type jet, the blower also need energy, but proportion is smaller much.
I calculated, with some other conditions, the energy for compressing the gas from 1 bar to 10 bar compare to 1 bar to 1.5 bar, the former is 7 times of the hinder.
From an actual example’s data, as to a current jet engine, 55% of the gas’ energy after combustion that can be utilized is used up by the turbine. That is for the compressor ahead.
Set 70% as the compressor efficiency in the current jet engine, after combustion 55% of energy that can be utilized is absorbed by turbine for compressor. We can get the rate of the actual efficiency to efficiency in theory is 72%
Set 75% as the blower efficiency in the new type jet, after combustion 55%/7=8% of energy that can be utilized is absorbed by turbine for the blower. We can get the rate of the actual efficiency to efficiency in theory is 97.8%
(List the formula per the definition of the heat efficiency: the work done by the gas to outside are same between the actual and theory, but the work from the others to gas is different. They absorbed same quantity of heat. I analyze the two jet engines’ the rate from the actual efficiency to efficiency in theory individually. I get the result upper)
Input the efficiency in theory of two types of jets I said before, the current jet 48%, the new type 42% (These data may not match the example upper, but have the value of reference)
The actual efficiency of the new jet is higher the current jet by 18.6%. So it is completely possible that the actual efficiency of the new jet is higher the current jet by 15- 20%.
The upper analyze is based with the efficiency data upper and ignore some secondary factors. I don’t list the calculation formulas but list the main data in the course. Anybody has interest, I’ll write out.

[DFINITLYDISTRUBD]

first off I'm sorry about the long delay in my responce. I've been quite busy lately with other responcibilities.

An automotive A/C system is the Air Conditioning (the system responcible for making cold air out of hot air for comforts sake)

[quote][Maybe you machine can work normally but it can’t fly, it is possible that the machine didn’t burning out enough fuel per second to provide enough force/QUOTE]
Considering that the turbo is only a 9" I'd say that it moves quite well!
I look at it this way: total engine weight-20lbs total weight moved 380 lbs+/- a few pounds@45mph. in my experience there aren't many engines that light that can move that much weight that fast, and lastly I get to have fun on the cheap!

[qumf]

Originally Posted by DFINITLYDISTRUBD

Considering that the turbo is only a 9"

what is the meaning of "a 9"'

regards

[qumf]

Originally Posted by qumf

Input the efficiency in theory of two types of jets I said before, the current jet 48%, the new type 42% (These data may not match the example upper, but have the value of reference)
The actual efficiency of the new jet is higher the current jet by 18.6%. So it is completely possible that the actual efficiency of the new jet is higher the current jet by 15- 20%.
The upper analyze is based with the efficiency data upper and ignore some secondary factors. I don’t list the calculation formulas but list the main data in the course. Anybody has interest, I’ll write out.

In last demonstration, I didn’t input high efficiency value for the new jet, If I input efficiency=44% (U=9.5, W=1.8 pls see the previous explanation about calculation of heat efficiency). Then refer to the previous demonstration about the rate of the actual efficiency to efficiency in theory of two jet engine individually. I conclude the actual efficiency of the new jet is higher than the current jet by 25.6%. It is very good.

[DFINITLYDISTRUBD]

9" referes to the outside diameter of the outer turbine on the turbo-charger (the portion of the turbo that is driven by the exhaust from the car or trucks engine). The inner "fan" which moves air perpendicular to the rotation of the turbine is the compressor which in this case is 3" in diameter.

Converting it to a jet engine is as simple as fabricating a combustion chamber,
ducting the output of the compressor to the aforementioned chamber with a reed valve between to prevent back-flash, ducting the combustion chamber to the turbine with a reed valve between , fabricating a nozzle to increase exit velocity of exhaust, and last but not least "fabbing up" a throttle body and injector assy. at the intake as well as adding a means of combustion in the combution chamber (glow or spark plug depending on fuel. the best for this aplication comes from the "Eberspacher" auxilery heaters found in older VW Vanagons it is both a glow plug and a spark plug in one when possible it is best to get the fuel and spark management guts with them as it simplifies powering the plugs and regulating fuel flow.)

Note: an oil tank, lines and circulator pump are necesary to prevent damage to the bearings of the turbine. (failure to provide adequate lubrication will cause mass destruction of said engine !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!)

2. Note: engine weight includes all componants necessary to allow the engine to function properly including fuel pump, battery, fuel management system, combustion management, oil tank and lines, turbine, combustion chamber and ducts, etc .