Quote:
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Originally Posted by EWright
How 'bout a clue in ENGLISH!!!!
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ONE STEP BEYOND (7)
I will work to explain that Lorentz’s transformations have not the scientific integrity.
In the well-known experiment of SR it is taken aim to obtain the same value of < c > in the train and on the perron. We will use this experiment also. If you wish you may take the world instead of the train. We measure the velocity of light on the world by the units kilometer and second. And its value is 300 000 km/s.
The train travels by the speed of < v >.
Lorentz’s equations transform the values of units. For example; if v = 60 % c
L’ = L.sqrt (1 –v2/c2) = 0.80 L
t’ = t (1 – v/c) / sqrt(1 – v2/c2) = 0.5 t
It means : One unit of meter in the train is 0.80 meter according to observer on the perron. And we must call the units according to its place (reference or relative system):
The unit of length in train = trainmeter ( = 0.80 railmeter ; for v = 0.60 c )
The unit of time in train = trainsecond (= 0.5 railsecond; for v = 0.60 c)
The unit of length on perron = railmeter ( = 1.25 trainmeter; for v = 0.60 c)
The unit of time on perron = railsecond ( = 2 trainsecond ; for v = 0.60 c)
Now we use Lorentz equations for t = 5 railsecond
x = c. t = 300 000 . 5 = 1 500 000 railkm ( c = 300 000 railkm/railsecond)
x’ = (x – vt) / sqrt (1 – v2/c2) = 600 000 / 0.80 = 750 000 trainkm
t’ = (t – vx/c2) / sqrt (1 – v2/c2) = 2 / 0.80 = 2.5 trainsecond
And our aim has obtained: c = x’ / t’ = 750 000 / 2.5 = 300 000 trainkm/trainsecond
It means we can assure the fixed value of the light’s speed by the units in relative system. We can calculate it by the units in reference system:
300 000 trainkm / trainsecond = 240 000 / 2 = 120 000 railkm / railsecond
What is this ? This is an evidence of the end of the theory SR. Because The units must be same to obtain the same fixed value of light’s velocity. This like that: If You give to your child every week 50 USD. After today you will may give him 50 japanese-yen according to Einstein.