This theory was developed and posted 1:20am , saturday, october 15, 2005 by Nicholis Justin Hill.
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Realistic Relativity
I want to start off with a hypothetical situation that explains how velocity and kenetic energy can not exist without more than one object. I will then move on to explain what happens once a hypothetical universe has more than one atom/object.
I want you to imagine a chalk board which represents space. There is a few atoms floating around in this space. Now, let's erase all of the other atoms and draw a single hydrogen atom. Now all that exists in this empty vacume is 1 atom. Hypothetically lets say this atom wants to travel around and find another atom to interact with. It floats here, than over there, than over here, but then it soon realizes it has no way of knowing how fast it is going and infact, no matter how much effort it puts into going fast, it still has no calcuable velocity. The atom has nothing to compare its velocity with. There is nothing in this hypothetical universe for this atom to interact with so this atom has no kinetic energy. The only way for it to be able to attain energy is to have another or object in the path or close area of the hydrogen atom (a reference point). Now we draw a second hydrogen atom. Once this is done we now have a universe with the ability to have motion, energy, aswell as velocity. These two atoms are now on a direct path for eachother, closing the distance between them at 10m/s. Although, it is impossible to tell which object is doing the motion simply because it depends if you are looking from object A and seeing object B come at you or looking from object B and seeing A come at you. Each atom sees the other coming towards them at 10m/s. (We assume zero energy is lost in this thought experiment). Each atom in its own reference frame assumes itself to be stationary and has zero velocity, but assumes the other atom is coming towards it at 10m/s or, vice versa, Each atom assumes they are heading towards the other atom at 10m/s and that the other atom is at rest. When the collision occurs, there is a brief moment where all the velocities are zero and no kenetic energy is apparent. Then, each attom feels a force (which does not matter if it feels foward or back for an atom). They each think they have either hit the other atom and sent the other flying away or have been hit by the other atom and now are fly away from eachother at 10m/s. It becomes apparent that there is no possible way to calculate which particle was the oringinal one in motion or even if they were both in motion. One atom could of been traveling 90m/s and the other could of been following it at 80m/s. The only fact is that there was an interaction between the two at a measured velocity of10m/s. Which is likewise applied to an entire universe coming near another universe. Each atom apparently thinks they each hit eachother at 10m/s. Here we have a situation where it is possible for the interaction to have occured at 20m/s.
Here we a drawing of this thought experiment with and the data representing each reference frame.
Moving on to Example A.
A 100kg ship takes off from earth to the moon and stops at the halfway point. It then measures from its reference frame to these two reference points and assumes to have zero velocity and in turn zero kinetic energy and affirms it is stopped(when we exclude the other of the visible objects in space).
E=1/2(M*Vsquared)
E=1/2(100*0squared)=0
It is stated that when you double your velocity (velocity refering to when we measure distance divided by time) it takes 4 times the distance to stop
than it does to stop when traveling half the velocity because your energy becomes 4 times greater each time you double your velocity.At this point the ship is at 0m/s according to the two reference points. There is not a possible way to go double than 0m/s and figure out if its energy increases 4 times, so the ship decides to start traveling at 1m/s to have somewhere to start this experiment. E=1/2(100*1squared)=50joules, as of now it has 50 times the energy it previously had at 0m/s. According to the ship it is leaving earth at 1m/s and also heading towards the moon at 1m/s. Each second that passes on the clock in the ship it covers 1 meter towards the moon and 1 meter away from earth covering a total of 2 meters when using the two reference points. The ship then doubles its velocity to 2m/s.
E=1/2(100*2squared) and now has 200joules of energy. 50x4=200, now it does have 4 times the energy because it doubled its velocity from 1m/s to 2m/s. But, now each second that passes by it covers 2 meters closer to the moon and 2 meters further from earth, covering a total of 4 meteres/second!. We apply that calculation E=1/2(100*4squared) and aparently now it has 800joules of energy, twice than before when it was only measuring velocity towards the moon. Now for a moment let us erase the earth from this experiment. The ship calculates it is now still
traveling 2m/s towards the moon by measuring how much distance it covers towards the moon or how much distance the moon is covering
towards the ship divided by the time. There is a person on the moon that measures the same calculations as the ship has. The ship then speeds
up to 4m/s again doubling its velocity. E=1/2(100X4squared)=800joules. It has now gained 4 times the energy that was calculated when going 2m/s towards the moon. Now I want to disect the equation and apply it to the experiment.
(V1) Velocity 1= the ship
(V2) Velocity 2=the moon
(M) Mass = the mass of the ship
At this point the ship and the moon are closing in at eachother at 4m/s according to today.
E=1/2(M*V1*V2)
E=1/2(100*4*4)=800joules again.
The equation says the moon and the SHIP are each traveling at eachother at 4m/s for a total combined speed of 8m/s also, according to E=1/2(M*Vsquared). The ship begins closing in near the moon. We now assume the ship is a solid ultra hardened ball of titanium (or any other kind of strong element that has the ability NOT to lose any energy during an impact) and the moon is likewise a solid ultra hardended ball of the same material and has a mass of 100,000,000,000kg's(or otherwise enought to not move). (now using physics today) The ship hits the moon square on dead center carrying E=1/2(100*4squared)=800joules. The inertia of the moon is so great that we assume it does not react to the ship hitting it. For a brief moment the ship is at 0m/s and has zero kenetic energy. Next the ship rebounds in the exact opposite direction at 4m/s away from the moon, and has now attained 800joules of energy again. From 800 joules to 0joules back to 800joules in the opposite direction. This we call the conservation of momentum/energy and when you add it up there was a total of 1600 jouls of energy involved to accomplish this task. Remember how we squared the velocity of the moon and the ship in previous equation (E=1/2(M*Vsquared) to figure out how much energy was in 1 object (the ship)
Using this equation, E=M*V1*V2 . E=100*4*4= 1600joules, equal to the total energy required to cause the ship to reverse direction like it did. This eqution (E=M*V1*V2) shows an object traveling towards another object has the potential to inflict the energy of E=M*Vsquared or E=M*V1*V2. With the 1/2 removed from the normal kenetic equation we understand that the conservation of energy or momentum(?) is the fact stating that two objects heading towards eachother are each coming towards eachother at the same speed for a potential energy force of twice the interpreted energy when using the Velocity of useing V= D/T. (which refers only from point A to B and exludes the other reference frame). So the reason for energy increasing 4 times when a velocity increases double is because the reference point in front of you is also coming at you the same speed.
Here is a drawing of a similar experiment where ball B can not be moved.
Application of my theory on E=mc squared:
-Energy is equal to mass times the speed of light squared in todays physics to determine how much energy is contained within atoms of a peice matter.
-Every action has an equal and opposite reaction as verified above.
-Light has the ability to apply force to all mass and can be affected by gravity.
-The speed of light is 300,000m/s and is considered to be a universal constant as we know it today.
It is just as possible that the force in which emmits the light is constant. This says that whatever causes the emmition of light must always have a constant mass. The force involved to cause light to travel at 300,000km/sec will cause the object emitting the light to experience the same force upon it, saying that there is a force faster than C, if we assume the source is the close to the same mass of a light particle. Cirtain physics forumlas show that when an object reaches the speed of light its mass increases towards infinaty and in turn to push this object you need an infinate force rendering the task impossible. Also physics today says time dialation will occur. The time it takes to get to a destination will be shorter in your reference frame. Aswell as a length contraction will occur which I do not fully understand except for distance appears to be decreased. If my theory is applied here, it is reasonably explained that the point in which you would aproach the speed of light in a ship(body of mass) you would be traveling twice the speed you would expect to be towards your destination at the same twice the speed away from your original point but not any more than two times in total. Your kenetic energy using E=(M*Vsquared) becomes much higher (infact double) than before explaining why mass would be interpreted to increase. As for maxing out at the speed of C, this could reasonably be explained that if you were using the fastest source in the universe we know of (which is light that travels at C) to power a ship using a light ejecting engine to reach the speed of C the force would eventually be split between the two objects or the speed of ship moving forward and the light leaving the engine would match putting a stop to all acceleration.
When a nuclear bomb does not release the same energy that E=mc^2 would tell you. It can logically be explained that the force that comes out of the bomb must apply the same equal opposite force inwards on the bomb causing a loss in excpected energy.
Conclusion of Realistic Relativity by:
Nicholis Justin Hill (Nick Hill)