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Old 04-21-2006   #1 (permalink)
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Help me with an equation.

I just may be onto something.. but as likely I am not..

I've been developing yet another branch onto the mass unifying theory of mine.. (dont worry I laugh with you on that one aswell).


I need some assistence with figuring something out.

I am trying to figure how big of a perfect circle a beam of light would make in 1 second.
I'm looking for the radius, and circumfrance of that circle...

I suppose you would say, Light travels 300,000km/sec (generally). So would light be able to travel in a perfect circular path with a circumference of 300,000km in one second? (and meet where it started?) sounds right...

So, what is the radius of this circle?


I am trying to discover something to do with discovering where 'frequencies' come from, and why they are there.

It is directly related to the observations I have been stating to do with time.

Things in the singularity (freeze point) of time have , no mass, no gravity, and do not change. like light, and charges, and magnetic fields? These functions exist in an apparent constant of "C".

Things in the variable curvature of time (in motion) have, mass, gravity, and change. Like matter.

I cant get to far into explaining where this all leads, as I am not even positive myself.

Thanks in advance for helping with the math question.

Last edited by arkain101; 04-21-2006 at 07:00 PM..
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Old 04-21-2006   #2 (permalink)
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Re: Help me with an equation.

C = 2*pi*r

300,000 = 2*pi*r
r = 150,000/3.14159...
r = 47746.5km


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Old 05-07-2006   #3 (permalink)
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Re: Help me with an equation.

Okay.

Speed of light: 299 792 458 m/s

Diameter of an atom: 1x10^-10m to 5x10^-10m

Visible Light Frequency Range: 4.3x10^14 Hz to 7.5x10^14 Hz

Circumfrence of an atom: C=Pi*D
C= 3.14x10^-10m

Trying to solve for how many times light will travel the distance of 3.14xx10^-10m per second and see how close to the frquency of light this is.
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