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Published by Little Bang 05-18-2008
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#1
By
Moontanman
on
05-18-2008
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| Re: Origin of the Universe,,,,Bang or no Bang |
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#2
By
Little Bang
on
05-18-2008
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| Re: Origin of the Universe,,,,Bang or no Bang Albert has already been proven right, I just want to see pluto admit to that fact. |
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#3
By
CraigD
on
05-19-2008
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| Quote:
A clock on Earth’s surface at the equator, however, runs faster (1.0000000003253 times) than one in a lower circular orbit (say a typical low-earth orbit of about 200 km AGL). A fun exercise is to calculate the altitude at which the clock on a satellite runs at the same speed as one on the surface. Everything need for the calculation can be found at the wikipedia articles “Earth”, “orbital speed”, “standard gravitational parameter”, “time dilation”, “gravitational time dilation”, and “speed of light”. | |
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#4
By
Little Bang
on
05-19-2008
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| Re: An exercise the application of relativity to satellites Craig, I do not understand why you are trying to confuse a simple statement. I never made any attempt to delve into the relativity aspects of time. Either a clock slows as it falls into a gravity well or it does not. Now if you have evidence that it does not please enlighten us. I notice that Pluto did not respond. |
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#5
By
modest
on
05-19-2008
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| Re: An exercise the application of relativity to satellites Quote:
Quote:
Quote:
If there is no difference in velocity between two observers who are situated higher and lower in a gravity well then I would agree that the lower observer has a slower proper time compared to the higher observer. Is this ok? -modest | |||
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#6
By
Little Bang
on
05-19-2008
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| Re: An exercise the application of relativity to satellites Yeah, that's just fine. |
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#7
By
CraigD
on
05-21-2008
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| Quote:
In the example you gave - a clock A on the surface of Earth, compared to a clock B in orbit - there’s more to consider than just their difference in altitude (In the case of a geostationary altitude, about 6378 vs. 42164 km from the Earth’s center). They are also moving at different speeds (about 465 vs. 3075 m/s). So both gravitational time dilation and time dilation due to speed must be taken into account. In the geostationary orbit case, the relative gravitational time dilation ( , the clock on Earth runs slower) is larger than the relative speed time dilation ( , the clock on Earth runs faster), so the net relative time dilation results in the clock on Earth running slower. If clock B is in a lower orbit, however, the relative speed time dilation is larger than the relative gravitational time dilation, and the clock on Earth runs faster than it.If you could eliminate velocity (for example, by raising clock B using a mast set at the geographic North or South Poll, rather than orbiting it), or eliminate mass (for example, have clock A and B fly in their usual circular paths far out in space), then their relative time dilation could be explained using only one of the time dilation equations. For a real-world example, however, both must be used. PS: This discussion of relativity seems to me off-topic, so if there are no objections, I’ll move it and perhaps other off-topic posts to a separate thread. | |
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